# Linux Shell Script Tutorial # Script to reverse given no # # Algo: # 1) Input number n # 2) Set rev=0, sd=0 # 3) Find single digit in sd as n % 10 it will give (left most digit) # 4) Construct revrse no as rev * 10 + sd # 5) Decrment n by 1 # 6) Is n is greater than zero, if yes goto step 3, otherwise next step # 7) Print rev # if [ $# -ne 1 ] then echo "Usage: $0 number" echo " I will find reverse of given number" echo " For eg. $0 123, I will print 321" exit 1 fi n=$1 rev=0 sd=0 while [ $n -gt 0 ] do sd=`expr $n % 10` rev=`expr $rev \* 10 + $sd` n=`expr $n / 10` done echo "Reverse number is $rev"